I think they are using flow rate and delta across the radiator to come up with the heat dissipated. Then they probably use delta from the air in sensors to the average of the two water sensors.
I still struggle with the whole Q = M X CP X dT equation myself with units but I think I got it.
To simplify it further and convert it to flow rate:
Q in watts = 263.43 x (Flow rate in GPM) x (dT in C)
So you need 263 watts to raise the delta 1 degree at 1 GPM
Or if you want to solve for dT
dT in Celcius = (Q in watts)/(263.42 x (Flow rate in GPM)
So for example, I've been testing with a 590 watt heat load at 1.5 GPM, so my dT would be 1.49 degrees across the radiator.
I think I need a beer, this stuff hurts..![]()
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