Phenom 9500 w/ MSI K9A2 Platinum

[justapost]

I still don't understand why you have one formula for two separate voltages?
You're postulating that there is a fixed relationship between the two independent voltages but my experimentation doesn't show this.

I was looking for a formular to calculate an single voltage for the cpu, whom I can use in a voltage vs. frequencies/temps/power consumption diagrams.

At 2200MHz I found two settings whom are both stable in the 30 minute prime95 criteria.

1,2V/1,0250V
1,185V/1,075V

Notation:
u= Average Voltage
u1 = cpu voltage
u2 = nb voltage

1,2V*4/5+1,025V*1/5 = 1,165V
1,185V*4/5+1,075V*1/5 = 1,163V

So this formular might help estimate the nb voltage needed for a different cpu-v. Just want so save time, as this stability testing takes alot more time with two voltage settings.
In words if you have a stable setting with a very low nb voltage, you will have an other stable setting at a 0,0125V lower cpu voltage with an 0,05V higher nb voltage.

EDIT: After a few overnight prime95 runs, the optimal settings seems to be the max of both possibilities. Now that does save time because you only have to find the two prime95-30minute-stable setting and get a good estimation of an 24hrs stable setting.

For what? The CPU VRM?

I doubt it uses that chip but my system is inside a case and it's jam packed in there, especially the CPU PWM area so can't check until I can take it out of the case which I won't be doing yet.

Nevermind,t hought you know what chips is on your mobo because you already did some nb pencil modding.