the graph is perf per watt
so if perf of 480 is 100, and power is 100
then the 580 would be perf of 115 for power of 85 resulting in
(115/85)/(100/100) =
135/100 = 135
=35% better perf per what, which is almost exactly what i was saying.
so because we know perf per watt, and perf, we can find the watt by doing simple algebra. (which i didnt do lol)




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