Quote Originally Posted by terrace215 View Post
Well, it looks like 32 byte/cycle is enough to keep up (assuming we need 1 (or 2, for the 128-bit hardware) cycle to accumulate the new 256 bit value into the running sum anyhow), so wouldn't it be roughly 2:1 in this case?
OK, it seems you have found such an ideal case. Not unlikely that this case
will be used as a synthetic benchmark ....

Regards, Hans.