Quote Originally Posted by bluehaze View Post
So you are saying the size of the chamber coming off the pump makes the difference? Because the hanging point for me which we discussed before was that the water will take the least path of resistance. So in a free flowing loop the chamber would aid the flow by allowing more water to be fed through each loop with the pump being the only restriction, with that I agree.

However once you add restriction to the loop that is now the governing factor of your flow. Therefore as long as the flow coming through the Y was greater than the restriction through each loop you wouldn't even need a chamber because the water will fill each loop until equilibrium is reached.

In otherwords, just throwing numbers out there, if you have a pump able to flow 5gpm and a Y able to flow 4gpm, now run two loops off that y each with a restriction no greater than 2gpm and both loops dump back into a res removing the restriction at the end of the loop, you will have 4gpm flowing "through the pump" with no chamber at all on the outlet (open loop) because the Y is the restriction.

Now introduce a restriction greater than the Y to each loop and say you have two loops each restricted to 1.5gpm so the max you can possibly flow through these loops is 3gpm and you throw them on the pump flowing 5gpm through the Y flowing 4gpm. In this case your pump can flow 5gpm your Y can flow 4gpm so the governing restriction is the dual loops that flow 3gpm combined. Your flow rate is now determined by the restriction of the indivdual loops not by the Y, nor the pump, nor by any chamber in between the individual loops and the pump correct?

In otherwords your pump can still flow the full 5gpm because there is no restriction at the end of each individual loop, it's getting fluid from the res so is capable of starting each pass through the loop fresh with the full 5gpm capablity.

Is there something wrong with this train of thought?
Your going to have to loop up with the Y's and see for yourself because I cant think of any other way to explain it. The D5 produces XXX amount of power. To move the same volume of water through a smaller pipe at the same speed requires more power. If more power isn't available, go with a bigger pipe...the "pipe through the T3 is B I G G E R lol.

When they say the Y is the restriction, they mean the section of the Y's through the pump itself.