Can anyone rate the primochill Typhoon III?

[bluehaze]

Yes and no. If you look at the helix (or spiral involute if you prefer lol) in the T3 it is MUCH deeper then a normal D5 Top. Almost double. Because I could not make it any wider (again the D5's impeller dictates the with of the waters path) I pretty much cheated and made it deeper so that I could DOUBLE that primary outlet and get a lot more water into the PEC. The PEC regulates the pressure as close to the pump head as I could get it so there is not a huge pressure loss.

The rest Skinnee covers pretty well in his article. basically the portion of the loop that is actually inside your pump is doubled. If you do the Y method on a regular pump top, the entire loop (loops) may be doubled, but the section through the pump is still the single, or same flow as before.

Think of it like this. Obviously there is no Y inside the pump, but the single line that there is in there is the same volume (or close to it) as 2 lines would be. So when the dual loops of the T3 come together and pass through the pump, the volume of that section is still near the volume of 2 lines or loops. In the Y method on a regular top that line is just one lines worth of volume.

And yeah, I love talking about this stuff too lol.

So you are saying the size of the chamber coming off the pump makes the difference? Because the hanging point for me which we discussed before was that the water will take the least path of resistance. So in a free flowing loop the chamber would aid the flow by allowing more water to be fed through each loop with the pump being the only restriction, with that I agree.

However once you add restriction to the loop that is now the governing factor of your flow. Therefore as long as the flow coming through the Y was greater than the restriction through each loop you wouldn't even need a chamber because the water will fill each loop until equilibrium is reached.

In otherwords, just throwing numbers out there, if you have a pump able to flow 5gpm and a Y able to flow 4gpm, now run two loops off that y each with a restriction no greater than 2gpm and both loops dump back into a res removing the restriction at the end of the loop, you will have 4gpm flowing "through the pump" with no chamber at all on the outlet (open loop) because the Y is the restriction.

Now introduce a restriction greater than the Y to each loop and say you have two loops each restricted to 1.5gpm so the max you can possibly flow through these loops is 3gpm and you throw them on the pump flowing 5gpm through the Y flowing 4gpm. In this case your pump can flow 5gpm your Y can flow 4gpm so the governing restriction is the dual loops that flow 3gpm combined. Your flow rate is now determined by the restriction of the indivdual loops not by the Y, nor the pump, nor by any chamber in between the individual loops and the pump correct?

In otherwords your pump can still flow the full 5gpm because there is no restriction at the end of each individual loop, it's getting fluid from the res so is capable of starting each pass through the loop fresh with the full 5gpm capablity.

Is there something wrong with this train of thought?