Quote Originally Posted by Vapor View Post
I get what you're saying...but that's not the case.

If you took a loop with a CPU block, a radiator, and other stuff, it would have a pressure drop curve of y= AX^3 + BX^2 + CX + D (well, D=0). If you doubled the components in serial, you would have a pressure drop curve of y= 2AX^3 + 2BX^2 + 2CX + 2D. Basically, you'd double the resistance....

But if you took those same components and split the (doubled up) serial loop into two parallel loops....the overall restriction is much lower than even AX^3 + BX^2 + CX + D (how much so depends on the Y split and all associated with that).
I've been trying to figure this out before. How do you find the restriction over the parallel loops (from before the first Y to after the second), assuming no restriction in the Y's/tubing/etc? If X is flow rate, and f(X) equals your first "y" from above, would it be 2*f(1/2*X)?