2.0ghz Barcelona gets 924s
2.8ghz K8 Opteron gets 1284s
2.0 x 8 = 16,000mhz
2.8 x 4 = 11,200mhz
16,000/924 = 17.316
11,200/1284 = 8.723
17.316/8.723 = 1.985 speedup factor.
edit - i'm assuming a dual quad and a dual dual here, but half the numbers (1 proc each) and you get the same... unless there's a number out somewhere in which case my bad
Does the SMP client work one work unit across all cores or is it one per core? I assume it is one per core in this calculation. One across all cores will be different numbers.







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