Case Design for Liquid Cooling

[Blauhung]

Late vote, but if it happens i will buy the bigger one that can fit the EVGA mobo


As for the whole parallel water cooling discussion.....
At the flow rates that just about everyone will be using in water cooling, you can very safely assume that the temperature of water entering the radiator and leaving the radiator are approximately equal as all of the coolant has hit a steady state.

here's the energy ballance on a series water cooling flow with 2 loads and 1 radiator

Qcpu1 + Qcpu2 = Qrad (the heat dissipated by the radiator at steady state is = to the heat generated by the 2 cpu's)
Qcpu = Tdelta * Fh2o / Rblock (since the input and output temp can be considered constant, the heat absorbed by the water in the block is going to be a function of the temp difference between the water and the CPU, the flow rate of the water, and resistance to heat transfer of the block)
Qrad = Tdelta *Fh2o / Rrad

so you end up with
((T1-Tw)*F1)/R1 + ((T2-Tw)*F2)/R2 = ((Tw-Ta)*Fr)/Rr (i substituted in the temp delta's here Tw being water temp, T1/2 being cpu temp, and Ta being air temp)

if you are in series, then the flow rates will all be equal so they all cancel out, you can also assume the temp and resistance to heat transfer on each block to be equal so you end up with
2*(Tc-Tw)/Rb = ((Tw-Ta)/Rr (simplified T1/T2 into Tc or core temp, and R1/2 into Rb or block resistance)
(Tc-Tw)/(Tw-Ta)=Rb/(2*Rr) for series

For paralell, you can assume that the flow rates at each block are 1/2 the flow at the rad
((Tc-Tw)*F/2)/Rb + ((Tc-Tw)*F/2)/Rb = ((Tw-Ta)*F)/Rr (F cancels again)
(Tc-Tw)/(Tw-Ta)=Rb/Rr for parallel

Now to solve these you need to list what you know
-lets assume that the Rb:Rr ratio is ~1 just to save on some math
-Qcpu = 100w (another easy #)

so for series here are our sets of equations
Q=(Tc-Tw)*F/R
(Tc-Tw)/(Tw-Ta)=1/2
after a bit of substitution you can get that
Tcser = QR/F +2QR/F+Ta = 3QR/F + Ta


and for parallel
Q=(Tc-Tw)*(1/2*F)/R
(Tc-Tw)/(Tw-Ta)=1
subs
Tcpar = 2QR/F + 2QR/F + Ta =4QR/F + Ta

so assuming that all the Q's R's and F's are equal between the 2

Tcseries/Tcpar = (3QR/F +Ta)/(4QR/F +Ta)

and this kinda shows that your core temp will be lower in series then in parallel.


In summary, your water temp is approximately constant, and running stuff in parallel really only results in lowering your flow rates in each block which drastically lowers your energy transfer efficiency and makes the thing you are trying to cool hotter.