-
Caught them in a lie
OK. Got them now. They're lying, unless they've managed to change the laws of physics.
Their results are impossible.
Air @ 25C has a density of 1.169kg/m³
Air has a specific heat capacity of 1012J/kgC
Air therefore has a thermal capacity of 1.169 x 1012 = 1183 J/m³C
Air-flow through their radiator is 5m/s, with an orifice area of 0.13m x 0.24m
That's 5 x 0.13 x 0.24 = 0.156m³/s
Therefore, the thermal resistance of the air-flow is:
0.156 m³/s x 1183 J/m³C = 184.55 J/sC
A Watt is a Joule/sec
Therefore the thermal resistance of the air is 185.55 W/C, or inverting, a C/W of 0.0054186
i.e. for each watt of heat energy dissipated into the air, the air will warm up by 0.0054186C
Koolance claim a heat dissipation of 9.62kW, or 9620W
9620 x 0.0054186 = 52.13C
i.e. to dissipate that amount of heat, the air MUST have risen by 52.13C above the inlet air temperature.
So the exhaust air MUST be 24.46 + 52.13 = 76.59C
This is basic thermal physics here.
Here's the crunch part. Their results claim that the water discharge temperature is 56.20C
i.e. In a total breakdown of the laws of thermodynamics, the water discharge temperature has somehow managed to exit the radiator at 20C less than the air discharge temperature.
THAT is impossible.
Last edited by Cathar; 06-17-2007 at 06:41 PM.
Posting Permissions
- You may not post new threads
- You may not post replies
- You may not post attachments
- You may not edit your posts
-
Forum Rules
Bookmarks