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Thread: Koolance's Response to Hardware Labs "The Copper Radiator Myth"

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  1. #11
    Xtreme Legend
    Join Date
    Nov 2002
    Location
    Melbourne, Australia
    Posts
    1,026

    Caught them in a lie

    OK. Got them now. They're lying, unless they've managed to change the laws of physics.

    Their results are impossible.

    Air @ 25C has a density of 1.169kg/m³
    Air has a specific heat capacity of 1012J/kgC

    Air therefore has a thermal capacity of 1.169 x 1012 = 1183 J/m³C

    Air-flow through their radiator is 5m/s, with an orifice area of 0.13m x 0.24m

    That's 5 x 0.13 x 0.24 = 0.156m³/s

    Therefore, the thermal resistance of the air-flow is:

    0.156 m³/s x 1183 J/m³C = 184.55 J/sC

    A Watt is a Joule/sec

    Therefore the thermal resistance of the air is 185.55 W/C, or inverting, a C/W of 0.0054186

    i.e. for each watt of heat energy dissipated into the air, the air will warm up by 0.0054186C

    Koolance claim a heat dissipation of 9.62kW, or 9620W

    9620 x 0.0054186 = 52.13C

    i.e. to dissipate that amount of heat, the air MUST have risen by 52.13C above the inlet air temperature.

    So the exhaust air MUST be 24.46 + 52.13 = 76.59C

    This is basic thermal physics here.

    Here's the crunch part. Their results claim that the water discharge temperature is 56.20C

    i.e. In a total breakdown of the laws of thermodynamics, the water discharge temperature has somehow managed to exit the radiator at 20C less than the air discharge temperature.

    THAT is impossible.
    Last edited by Cathar; 06-17-2007 at 06:41 PM.

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