hmm isn't the current stated in AMD datasheets?
(59.8W = 1700+ Tbred B CORE)
And I should be 59.8w/1.6v=37.375A and 37.4Amps is in AMD datasheet.. So..
It would also be about R = U / I = > 1.6/37.375 = 0,042809364548494983277591973244147 ohm =)
P= U²/R => 1.6V²/0.042809364548494983277591973244147 = 59.800000000000000000000000000206watts
So i think that u got the right numbers now. Anyone really good for this like an master in electronics or anything that would clear this out what the cpu would radiator at say 2800mhz 2.2V
I can clearly see that it should radiate 113,05937500000000000000000000039W with 2.2V at default frequency.
Then 2800-1467=1333 =) 1333/1467=0,90865712338104976141785957736878 over default clock
113,05937500000000000000000000039Watt*1,9086571233 8104976141785957736878 = 215,79158145875937286980231765556Watts
And this is somthing totalywrong if this isn't right it should be and thats means that.
Overclocked Watts = Default Watts * (Overclocked Mhz \ Default Mhz) * (Overclocked Vcore \ Default Vcore)² allso is right!!
Thats mean that Morphling is watercooling a 215W(100%) cpuat 88% it will be 189,89659168370824812542603953684Watts know thats a challange for a prome thats only can cool about 180W :P
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