You start with the FSB termination voltage, or just FSB voltage, which on "auto" is equal to 1.2000v. Under the old BIOS you can go from "auto" up to "63," which is equivalent to 1.3125v (or 1.313v rounded) in the new BIOS revisions. That's a difference of 0.1125v, which divided by 63 comes out to 1.8 mV per value.
You then go to the GTL voltages, which for a Q6600 are at 2/3 of the FSB voltage at "auto." 2/3 is of course 66.67%, or .667 the value of the FSB voltage, which with everything at "auto" is ~.800v for the GTLs. At the maximum FSB voltage, the "auto" GTLs are still .667 the value, which becomes ~.875v.
Under the old BIOS, you would go backwards to "80" and then in steps of 5 back down to auto, "75," "70," "65," and so forth. At the maximum, which is "80," the GTLs will be 68.7% or .687 the FSB voltage. Since there are 16 positive values, and you are gaining 2% at the maximum, each value is .125% more of the FSB voltage. Hence, "5" would be 66.7% + .125%, "10" would be 66.7% + .250%, and so forth. At "auto" FSB voltage, "80" is ~.824v and at maximum FSB voltage it is ~.902v.
You can also lower the GTL values by 2%, down to 65.7% or .657 the FSB voltage. At the "auto" FSB voltage this would be ~.788v and at the highest this would be ~.862v. You can see why it would be difficult to read a chart - you'd have 63*33 values, a considerable amount. It is easier to calculate on-the-fly using my basic rules.




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