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Thread: PA 120.3 and MCR320 in parallel

  1. #26
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    Quote Originally Posted by SDatl404 View Post
    Are you saying that the greater the flow the higher the resistance gets? I have a hard time choking down that water cooling pumps could push enough water for you to even reach noticable loss in flow due to radiator configuration.

    Saying the other radiator gets cooler water is like saying half of a larger radiator gets cooler water. If you didn't need the water colder after it left the first one why have a second?
    Yes. I'm sorry, I'm afraid I can't help you if you did not notice that from the various charts, etc. that are available to the public. I can't help you either if you don't see how 2 radiators would be useful.

    sick g4m3r, like I said you must approximate. Plug in different equations y=ax^2, and check the values to see if they approximately line up...in the end its still an approximation.
    Last edited by serialk11r; 06-15-2007 at 10:49 PM.
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  2. #27
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    Quote Originally Posted by serialk11r View Post
    Yes. I'm sorry, I'm afraid I can't help you if you did not notice that from the various charts, etc. that are available to the public. I can't help you either if you don't see how 2 radiators would be useful.

    sick g4m3r, like I said you must approximate. Plug in different equations y=ax^2, and check the values to see if they approximately line up...in the end its still an approximation.
    lol... You claimed that the water coming out of the first radiator was colder, like it's a bad thing. This makes no differnace on the total cooling of the system. It's still passing through 2 radiators. Wether at the same time or one after the other it's all the same. Unless so one can logicly prove other wise. All I said was that if the water being cold enough after leaving the first why do you need a second?
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  3. #28
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    The way to "add them up" is easy enough.

    For two radiators in series, you just add together the two PQ curves for a single radiator. Add all the PQ curves together (rads plus block + tubing) and see where that intersects the pump PQ curve.

    For two radiators in parallel, it's a little trickier. Resistance is proportional to the flow rate squared. At half the flow through each radiator, there's a quarter of the pressure drop, so what we do is take the curve for a single radiator, and divide each point by 4. We then add that curve to the curves for the block + tubing, and see where that intersects with the pump. There is the added restriction of the 2 x Y's though (the Y-split/join itself, and the tubing-Y-barb interface's), and that all needs to be factored in.

    I reflected all that in the curves that I presented above.

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    Quote Originally Posted by Cathar View Post
    So what you're basically saying is that you'd prefer to trust your assumptions, over those who have actually tested it.

    Parallel will give the loop more flow, for sure. How much more? How much are you waving your hands and simply assuming here? Here's a calculated plot based upon established pressure drop figures:



    In series, the radiators will have ~5.3LPM flowing through the system and each radiator.

    In parallel, the radiators will have ~2.75LPM flowing through them, and ~5.5LPM flowing through the system.

    There will be an extremely minor benefit at the waterblocks for moving from 5.3 to 5.5LPM, and a definite deficit at the radiators for dropping from 5.3LPM to 2.75LPM.

    The two effects do counter-oppose each other to a certain degree. Which one "wins" depends on a number of factors, but for the general case with modern waterblocks, the performance loss at the radiators outweighs the minor waterblock benefits through the small flow-rate increase.

    The differences are small though, I'll grant you that. They are small enough such that many people with 1C resolution on their CPU's won't notice it, but will typically range in the fractions of a degree, but in almost all circumstances should favor the in-series configuration. If people see differences larger than that, something else has changed.

    The larger the radiators, the higher the initial flow-rates, and the more powerful the fans, then it is more likely that an in-liquid-parallel config will win, but once again, the differences are never large, and certainly NEVER larger than the waterblock performance differences between the disparate system flow-rates.
    ? Would having two PA120.2 in series double the heat dissapation?

  5. #30
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    Quote Originally Posted by lilflippy View Post
    ? Would having two PA120.2 in series double the heat dissapation?
    Good point. Not quite. The water discharge from the first radiator is cooler, thereby decreasing the performance of the second radiator in the series. The significance of this depends on the flow-rate. At 5.3 LPM in the scenario, we're talking about a ~8% reduction in the performance of the 2nd radiator. That would translate into roughly a ~0.04C increase in the system water-temperature for the scenario, or not really enough to sway which was preferable in any significant fashion.

  6. #31
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    OT - Cathar is this another bike accident?!?!

  7. #32
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    Quote Originally Posted by Cathar View Post
    I took a chance on a worn front tyre at one of the world's fastest motorcycle race-tracks, that being Phillip Island.
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    OT - Cathar is this another bike accident?!?!
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  8. #33
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    So basically the differences are small enough, that it probably depends more on how the tubing is run and the restrictions of the Y's.

    One thing I don't understand is if the flow rate through a radiator is lower, why does that mean less performance? It seems to me that the longer the water is in the radiator, the more opportunity there is to dump heat into the air. Won't slower flow make the temp delta (between incoming and outgoing water) greater ?

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  9. #34
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    Quote Originally Posted by montyshaw View Post

    One thing I don't understand is if the flow rate through a radiator is lower, why does that mean less performance? It seems to me that the longer the water is in the radiator, the more opportunity there is to dump heat into the air. Won't slower flow make the temp delta (between incoming and outgoing water) greater ?

    ]Monty[
    I would lean logically towards that conclusion too, in our application i suspect that their is not enough heat in order to dissipate through both radiators as the amount of heat that is transfered out of the radiator increases with the difference between it and surrounding air. If we had a higher temperature then we would see a bigger cooling difference if the second radiator was in series or parrallel because it would compensate for the heat that could not be removed in the first pass. This is the same principal as why there is not just one tube but runs of tubes in the radiator, i.e. multiple passes, and since the radiators are geared towards our temperature and efficiencies we would have to have extreme conditions before we saw a benefit.
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  10. #35
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    Quote Originally Posted by Cathar View Post
    Wow! Mind like a steel trap eh? Can't hide anything from you, can I?

    What's the grinning smiley for? Schadenfreude?
    I'm morbidly amused that you had another fall after the seriousness of your last one (if it indeed is a new fall).

  11. #36
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    Quote Originally Posted by montyshaw View Post
    Won't slower flow make the temp delta (between incoming and outgoing water) greater ?
    (sigh)

    I'll pull out ye olde racetrack analogy.

    If I'm a molecule of water, circulating around a water-cooling loop, I'm just going around and around and around. It's just like being a race-car on a race-track at a fixed speed. The time I take to travel through the radiator is like the time spent travelling down the main straight of the race-track.

    If the race-track is 5 miles long, of which the main-straight (radiator) is 1 mile long, in the space of 1 hour, how much time per hour do I spend on the main-straight if I'm travelling at a fixed speed of 60mph, 120mph, or 180mph?

    The answer is that the speed doesn't matter of course. I spent 1/5th of my time on the main straight. 'cos the straight is 1 mile long out of 5. Even if I travel at twice the speed around the circuit, it'll take me half the time to get from the start to the end of the main straight, but because I'm going twice as fast everywhere else, I'll be on the main-straight twice as often. i.e. No matter how fast I travel, I'll be on the main-straight for 12 minutes out of every hour.

    Now common physics tells us that the rate of heat-exchange is proportional to the temperature difference between an object, and something else that's cooler than the object. If I'm a molecule of water, and air is cooling me (by way of the air cooling the metal tubes inside the radiator that I'm flowing through), then the longer I spend in the radiator, the cooler I will get (that's good), BUT, the cooler and closer I get to the air-temperature, the less quickly I'll lose heat (that's bad). The two cancel each other out. So why does higher flow results in better performance?

    The more quickly I rush around, the more likely I'm going to be tumbled about (think white-water rapids as opposed to a smooth slowly flowing river). This means that I'm going to get tossed against the cool metal walls of the radiator more often, rather than just cruising along down the middle of the tube, only passing heat slowly to water molecules beside me that are only a little cooler than I, because they are beside another molecule, and then beside another molecule, before we get to the cold metal wall. i.e. water sucks for transferring heat if it's not getting mixed about and thrown against the cold walls.

    Hope that explains it in a "simple" manner that is intuitive, obvious, and directly counters the "slower flow is better" argument.
    Last edited by Cathar; 06-16-2007 at 10:25 AM.

  12. #37
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    Cathar....are you assuming a perfect splitter? i.e., a Y-splitter that has zero restriction

    Since I don't think one exists....granted they're not very restrictive, but considering there is restriction, that would lower the flow of the parallel setup slightly, giving a super-slight advantage to series (and getting closer to your <.2C difference, rather than the calculated ~.1C).

    Maybe it comes down to whatever is easiest to tube?

    BTW, I don't think I've said this yet, but I REALLLLLY like your wholistic system simulator program you have there....

  13. #38
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    Quote Originally Posted by Cathar View Post
    Hope that explains it in a "simple" manner that is intuitive, obvious, and directly counters the "slower flow is better" argument.
    It did for me

    I'm learning some thing new here everyday.

  14. #39
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    ^ wow excellent explanation!


    so if i wanted to add the pressure drops of a fuzion, 2 MCR 320s in series, 1/2" tubing, and a MCW60:

    .5GPM~.4PSI drop
    1GPM~ 1.8PSI drop
    1.5GPM~ 3.45PSI drop
    2GPM~ 5.5PSI drop


    so with these numbers of flow vs pressure drop (PSI), how would I intersect this with the D5 PQ curve, of flow vs pressure (not drop)??

  15. #40
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    Quote Originally Posted by Cathar View Post
    So why does higher flow results in better performance?

    The more quickly I rush around, the more likely I'm going to be tumbled about (think white-water rapids as opposed to a smooth slowly flowing river). This means that I'm going to get tossed against the cool metal walls of the radiator more often, rather than just cruising along down the middle of the tube, only passing heat slowly to water molecules beside me that are only a little cooler than I, because they are beside another molecule, and then beside another molecule, before we get to the cold metal wall. i.e. water sucks for transferring heat if it's not getting mixed about and thrown against the cold walls.

    Hope that explains it in a "simple" manner that is intuitive, obvious, and directly counters the "slower flow is better" argument.
    I think this is a key point that people fail to understand. Your great analogy makes it a lot easier to understand.
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  16. #41
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    cathar, nice explanation, thankyou i knew all about the time spent in the rad being the same, but never thought of the water rapids
    after the PSU i'm planning on watercooling the ball bearings in the fans...

  17. #42
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    Quote Originally Posted by sick_g4m3r View Post
    so if i wanted to add the pressure drops of a fuzion, 2 MCR 320s in series, 1/2" tubing, and a MCW60:

    .5GPM~.4PSI drop
    1GPM~ 1.8PSI drop
    1.5GPM~ 3.45PSI drop
    2GPM~ 5.5PSI drop


    so with these numbers of flow vs pressure drop (PSI), how would I intersect this with the D5 PQ curve, of flow vs pressure (not drop)??
    It's somewhat involved.

    Download this tubing/fitting pressure drop calculator. It's what I use.

    Using established measured flow/p.d. results for your various items, manually calculate the total system pressure drop for at least 5 points in the range from 0.5gpm (2lpm), to 2gpm (or 8lpm).

    We then model a curve against our plot points (via any decent least-differences curve modelling software) using the formula "a*flow^b + c*flow". Model for a, b, & c. This formula is accurate enough for modelling flow-resistance, and is typically what is used when you see the smooth line PQ graphs for various things (but NOT for use with pump PQ curves).

    Plot our curve onto a graph, and then verify that the curve matches our calculated data points to a fair degree of accuracy. There are always going to be some inherent small amounts of error, primarily derived from the margins of error in the measurements of the pressure-drops of the blocks/radiators.

    What this does is gives us a smooth curve that fills in the gaps between the data points.

    We then plot that curve over the PQ curve for the pump, and determine the point of intersection.

  18. #43
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    ^ thanks a ton cathar! Thats the direction I was heading, but what I dont understand is how can you plot this when one curve is pressure drop, and the pump curve is attainable pressure

  19. #44
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    Thanks Cathar. Great explaination! Now I just feel dumb

    ]Monty[
    Last edited by montyshaw; 06-19-2007 at 06:04 AM. Reason: speeling :)
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  20. #45
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    I did it!!

    It wasnt pretty but i did it. I used a QuadReg to get the components' curve, and exponential reg to get the D5's curve.


    And in the end I ended up with (VERY rough):

    1.55GPM @ 3.63PSI of pressure.

    1.55 GPM for a D5 on two MCR320s, a MCW60, and a Fuzion is not bad at all!!!

    That seems too good, but I think I did it right.

  21. #46
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    BUMP

    sorry, i just want to know if these calculations seem right. Seems a little too good.

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