Originally Posted by
Cathar
OK. Got them now. They're lying, unless they've managed to change the laws of physics.
Their results are impossible.
Air @ 25C has a density of 1.169kg/m³
Air has a specific heat capacity of 1012J/kgC
Air therefore has a thermal capacity of 1.169 x 1012 = 1183 J/m³C
Air-flow through their radiator is 5m/s, with an orifice area of 0.13m x 0.24m
That's 5 x 0.13 x 0.24 = 0.156m³/s
Therefore, the thermal resistance of the air-flow is:
0.156 m³/s x 1183 J/m³C = 184.55 J/sC
A Watt is a Joule/sec
Therefore the thermal resistance of the air is 185.55 W/C, or inverting, a C/W of 0.0054186
i.e. for each watt of heat energy dissipated into the air, the air will warm up by 0.0054186C
Koolance claim a heat dissipation of 9.62kW, or 9620W
9620 x 0.0054186 = 52.13C
i.e. to dissipate that amount of heat, the air MUST have risen by 52.13C above the inlet air temperature.
So the exhaust air MUST be 24.46 + 52.13 = 76.39C
This is basic thermal physics here.
Here's the crunch part. Their results claim that the water discharge temperature is 56.20C
i.e. In a total breakdown of the laws of thermodynamics, the water discharge temperature has somehow managed to exit the radiator at 20C less than the air discharge temperature.
THAT is impossible.