Originally Posted by
Martinm210
Great test!
The calculations go something like this:
q=(specific heat of H20)X(grams of H20) x dT
specific heat of water =(4.18 J/g-K)
1ml H20= 1 grams H20
dT is the change in temperature over an hour
There is 3,600 Joules per watt-hour, so
Watts = Joules/3600
This will tell you how many watts was entering the water. I did this for the Alphacool AP1510 and came up with 16watts, I did it for the CPX-1 and came up with 6 watts, and I even tried it on my Q6600 with Prime95 and came up with around 130watts. It's an interesting experiement.