View Full Version : Equation for CFM @ 12v .vs CFM @ 5v
J-Mag
05-09-2005, 02:55 PM
Now I know that this is probably not possible for exact numbers due to variations in fan construction.
However, I really don't care if it is an approximation b/c most manufacturer's tend to lie anyway...
Essentially, I was wondering If I could take the rated 12v CFM or dba and convert it to what it "should" be at 5v.
Thanks
Agr3sive
05-10-2005, 09:00 AM
If i understood your question right, I would imagine it to be just under half as there is no regulators, its just direct power, ie-
100cfm @12v
45cfm @5v
Just the same if you could manged to get 18v down one line i would guess the cfm to be 150, hope this helps
Holst
05-10-2005, 09:31 AM
This will depend on the fan itself.
Some wont even spin at 5v....
Does it matter if you know?
I dont think you could work it out unless you do lots of maths. Better to just test it.
Dba is not a linear scale anyway so that definately wont work on a ratio.
AMD-me
05-10-2005, 02:16 PM
I agree, I think fin design and motor efficieny need to be taken into account to get a accurate measurement.
J-Mag
05-10-2005, 04:52 PM
This will depend on the fan itself.
Some wont even spin at 5v....
Does it matter if you know?
I dont think you could work it out unless you do lots of maths. Better to just test it.
Dba is not a linear scale anyway so that definately wont work on a ratio.
True but you could always keep the curve rate in mind...
It's not like marketing people don't do this all the time. I give my left nut if 90% of specs out there are altered, guessed, or rounded.
jellybeard999
05-10-2005, 05:02 PM
I give my left nut if 90% of specs out there are altered, guessed, or rounded.
They ARE ... you owe me that nut :woot: :)
rick_fx
05-10-2005, 05:09 PM
Lol!
craig588
05-10-2005, 05:12 PM
Just some numbers here, I havn't done any measurements. Half voltage=half amperage = quarter wattage = quarter of the ability to move air. The formula goes like this VA=W You are using 42% of the rated voltage, so multiply the rated amperage by that and multiply the modifyed values and compare it to the fans rated wattage. That might be aproximately the % of the full CFM that the fan will push.
Rippthrough
05-11-2005, 02:04 AM
Problem is that then fan blades won't be at peak efficency anymore, the motor porbably wont be either, so you need to take of a bit for that too, and even then you still only get an estimate.
$a1Ty
05-11-2005, 06:11 AM
is the fan rpm a linear scale with voltage
J-Mag
05-11-2005, 08:44 AM
They ARE ... you owe me that nut :woot: :)
Shipping Addy? :stick:
Btw, I had not had the ability to :rehab: before i made that post, which is why my thoughts were backwards...
Edit: I am not sure if you follow... the Ganja Banana Legacy...
J-Mag
05-11-2005, 08:47 AM
is the fan rpm a linear scale with voltage
It seems so... until obviously the cutoff point...
craig588
05-11-2005, 10:43 AM
is the fan rpm a linear scale with voltage
RPM != CFM
J-Mag
05-11-2005, 10:54 AM
RPM != CFM
Definately the case, but after starting voltage i think RPM cales close to linear. However I believe the RPM to CFM scale is more like an "S" curve.
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